answers to 3 numerical analysis program

已完成 已发布的 Feb 3, 2016 货到付款
已完成 货到付款

i want the C++ expert to break the math code and give me C++ code for it as requested. once confirmed ill be sharing the questions.

But the requirement is on an urgent basis. I need to submit the assignment well before 5th Feb 1PM.

C++编程

项目ID: #9548947

关于项目

15个方案 远程项目 活跃的Feb 4, 2016

授予:

tarlanbakirli

Hi. I want to let you know that I can do this project for you. I have experience on implementing algorithms, mathematical problems in C++ and solved many competition problems. If you feel convenient working with me, p 更多

₹1050 INR 在1天内
(4条评论)
1.2

有15名威客正在参与此工作的竞标,均价₹3972/小时

utkarshkatiyar19

Hi. i have a lot of knowledge in numerical analysis. I can easily help you with this project in given time. we can have a chat about it. thanks

₹2000INR 在1天里
(323条评论)
7.4
EngMah

hi I am an expert c++ programmer also i studied numerical analysis as a selective subject during my study as in computer engineering I hope we discuss details in PM thanks in advance

₹2555INR 在1天里
(30条评论)
4.7
idleswell

Hello, I have 25 years experience programming in C++. What is this project? I will revise my bid when you provide full specifications. A milestone payment for the full budget for this project must be deposited wi 更多

₹39128 INR 在3天内
(3条评论)
4.1
codistanpk

Hi. I would love to work on your project. I have excellent c++ programming skills and have won iEEE xtreme programming competition. Kindly share the questions and feel free to ask any question you have. Thank you f 更多

₹1000INR 在1天里
(5条评论)
3.0
kspratik

• Very good experience in algorithm development. Have implemented few IEEE papers as well. • Very good experience in application development using C++, AutoIt and C# • Highly adaptable and deadline oriented • Po 更多

₹1450INR 在1天里
(0条评论)
0.0
AnoopPN

I am quite good at problem solving using c++.So I think I am the best person who can solve your problem.

₹1300INR 在1天里
(0条评论)
0.0
vishalpvaza

A proposal has not yet been provided

₹1650INR 在1天里
(0条评论)
0.0