Thermodynamics work

Aeronautical & Aerospace Engineer, excellent and have a great experience in Thermodynamics analysis, modelling and simulation.

Hello, My name is Emmanuel Nwose. I am a chemical engineer. I have seen your posting and I am willing to solve the question. Kindly contact me for further enquiries. Thank you Sincerely, Emmanuel Nwose.

I am expert in chemical engineering including fluid flow and thermodynamics contact me for help in similar subject areas

Dear Sir, I am Chemical Engineering Student doing my post graduation at IIT Kanpur. The problems you have given are of basic under graduate level. I have worked as a tutor in my institute and know how to present solution in comprehensible manner to students. I have already made the solutions to all the problems and I can send it to you at the earliest. Thanking You

I have completed such assignments in past too. The time you will invest in reviewing other's bids, in the same time I can provide you all the answers, If you award me this project. Lets start the work. you will get your answers soonest. Even attaching two answers with this message itself as below. Ans. 2: Relation between temperatures measured in units Celsius degree and kelvin is as follows: Temp in kelvin = Temp in degree Celsius + 273.15 It is a linear relation which can be concluded to the result that absolute temperatures on these above two different scales (units) differ by 273.15 but whenever we talk about “change in temperatures”, there will not be any difference in these two units. A 70 degree Celsius change in temperature is same as 70 kelvin degree change on Kelvin scale. So the answer is: “The rise in temperature is 70 degree kelvin.” Ans.3: Temperature of ambient air is -40 degree Celsius. Relation between other temperature units and degree Celsius are following, using which temperature in respective units can be easily calculated: (a.) F = (9*C/5) +32 = (9* (-40)/5) +32 = (-40) , so in Fahrenheit units ambient temperature is -40 degree Fahrenheit. (Note that at -40 degree Celsius, both Fahrenheit scale and Celsius scale co-insides.) (b.) K = C+273.15 = -40+273.15 = 233.15, so in kelvin units, temperature is 233.15 degree kelvin. (c.) R = (9*C/5) +491.69= (9*(-40)/5) +491.69 = 419.69, so in Rankine units ambient temperature is 419.69 degree Rankine.

I know well about thermodynamics and i am sure i am able to help u out in this qns.........................

Hi, I have done my BTech and MTech in Aerospace Engineering from IIT Kanpur, India. Currently, pursuing PhD at the same place in stability analysis of unsteady flows. The content of the project, i.e. the question set provided by you, is based the fundamentals that we have been studying for a long time now. I just completed all the questions before bidding for the project to ensure faster submission. If the bid is accepted. I can type the things and provide the answer sheet. Please contact me based on your suitable time. Thank you.

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